Answer for If a car moving with 36 km/h increases its speed to 54 km/h in 10 seconds, find (i) acceleration and (ii) distance covered by the car at this time.

→ given÷

=> car moving with 36 km/hr increased its

=> speed to 54 km/hr

=> time taken = 10 seconds.

→ to find ÷

=> initial velocity = U = 36 km/hr.

=> 36 X 5/18 = 10 m/s.

=> Final velocity = V = 54 km/hr.

=> 54 X 5/18 = 15 m/s.

=> Time taken = 10 seconds.

→ 1) = to find acceleration

From newton’s first equation of kinematics.

=> v = u + at

=> 15 = 10 + 10a

=> 5 = 10a

=> a = 5/10 = 0.5 m/s²

→ 2) = distance covered by the car at this time

=> From newton’s second equation of kinematics.

$s=ut + \frac{1}{2}at^{2}$

$s=10\times10+\frac{1}{2}\times\frac{1}{2}\times10\times10$

=> s = 100 + 25

=> s = 125 m.