→ given÷
=> car moving with 36 km/hr increased its
=> speed to 54 km/hr
=> time taken = 10 seconds.
→ to find ÷
=> initial velocity = U = 36 km/hr.
=> 36 X 5/18 = 10 m/s.
=> Final velocity = V = 54 km/hr.
=> 54 X 5/18 = 15 m/s.
=> Time taken = 10 seconds.
→ 1) = to find acceleration
From newton’s first equation of kinematics.
=> v = u + at
=> 15 = 10 + 10a
=> 5 = 10a
=> a = 5/10 = 0.5 m/s²
→ 2) = distance covered by the car at this time
=> From newton’s second equation of kinematics.
=> s = 100 + 25
=> s = 125 m.