→
given÷
=> car moving with 36 km/hr increased its
=> speed to 54 km/hr
=> time taken = 10 seconds.
\rm \to \: \orange{{ \underline{to \: find \div }}}→
tofind÷
=> initial velocity = U = 36 km/hr.
=> 36 X 5/18 = 10 m/s.
=> Final velocity = V = 54 km/hr.
=> 54 X 5/18 = 15 m/s.
=> Time taken = 10 seconds.
\rm \to \: 1) = to \: find \: acceleration→1)=tofindacceleration
From newton’s first equation of kinematics.
=> v = u + at
=> 15 = 10 + 10a
=> 5 = 10a
=> a = 5/10 = 0.5 m/s²
\rm \to \: 2) = distance \: covered \: by \: the \: car \: at \: this \: time→2)=distancecoveredbythecaratthistime
=> From newton’s second equation of kinematics.
\rm \to \: s \: = ut \: + \frac{1}{2} a {t}^{2}→s=ut+
2
1
at
2
\rm \to \: s \: = 10 \times 10 + \frac{1}{2} \times \frac{1}{2} \times 10 \times 10→s=10×10+
2
1
×
2
1
×10×10
=> s = 100 + 25
=> s = 125 m.