# Answer for If a car moving with 36 km/h increases its speed to 54 km/h in 10 seconds, find (i) acceleration and (ii) distance covered by the car at this time.

given÷

=> car moving with 36 km/hr increased its

=> speed to 54 km/hr

=> time taken = 10 seconds.

\rm \to \: \orange{{ \underline{to \: find \div }}}→
tofind÷

=> initial velocity = U = 36 km/hr.

=> 36 X 5/18 = 10 m/s.

=> Final velocity = V = 54 km/hr.

=> 54 X 5/18 = 15 m/s.

=> Time taken = 10 seconds.

\rm \to \: 1) = to \: find \: acceleration→1)=tofindacceleration

From newton’s first equation of kinematics.

=> v = u + at

=> 15 = 10 + 10a

=> 5 = 10a

=> a = 5/10 = 0.5 m/s²

\rm \to \: 2) = distance \: covered \: by \: the \: car \: at \: this \: time→2)=distancecoveredbythecaratthistime

=> From newton’s second equation of kinematics.

\rm \to \: s \: = ut \: + \frac{1}{2} a {t}^{2}→s=ut+
2
1

at
2

\rm \to \: s \: = 10 \times 10 + \frac{1}{2} \times \frac{1}{2} \times 10 \times 10→s=10×10+
2
1

×
2
1

×10×10

=> s = 100 + 25

=> s = 125 m.